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  • Prize to solve this problem

    I'll give a free red tiki mat to whoever can solve this problem.
    Use a quadratic equation to find two real numbers that satisfies the situation, or show that no such numbers exsist.
    Their sum is 12 and their product is -28
    good luck algebra two students. lololol.
    i look forward to seeing some answers.
    EDIT
    i changed the problem, however the previous attempts were a wrong set up so it doenst really change anything.
    Last edited by Zaris; 09-29-2006, 01:48 PM.
    Take a look at my past signatures and avatars! And maybe some extra stuff! http://www.picturetrail.com/gallery/...ris221&x=0&y=0

  • #2
    Re: Prize to solve this problem

    Originally posted by Zaris View Post
    I'll give a free red tiki mat to whoever can solve this problem.
    Use a quadratic equation to find two real numbers that satisfies the situation, or show that no such numbers exsist.
    Their sum is 7 and their product is 14.
    good luck algebra two students. lololol.
    i look forward to seeing some answers.
    Is this your homework?

    :lmao:

    Comment


    • #3
      Re: Prize to solve this problem

      Wait, there's no number that does that...And if I get it right, I'll brag about it myself


      Comment


      • #4
        Re: Prize to solve this problem

        Originally posted by SnapplePlucked View Post
        Is this your homework?

        :lmao:
        Originally posted by SnapplePlucked View Post
        Wait, there's no number that does that...And if I get it right, I'll brag about it myself

        Its ONE problem on my homework, its actually quite easy if you know how to do it. And have a good calculater. But no im already done with this homework, ive moved onto civics but no that is not the answer. Ill let you know that the answer is a set of ordered pairs..
        Take a look at my past signatures and avatars! And maybe some extra stuff! http://www.picturetrail.com/gallery/...ris221&x=0&y=0

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        • #5
          Re: Prize to solve this problem

          I'm in Pre-Algebra so I knew I was going to be of no help...

          Comment


          • #6
            Re: Prize to solve this problem

            Never did anything like this in Algebra. Idk but how is a set of ordered pairs a solution doesn't make sence if their real numbers or whatever.

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            • #7
              Re: Prize to solve this problem

              only in pre-algebra, but i will try...

              Made by me

              Comment


              • #8
                Re: Prize to solve this problem

                It's probably really easy but I never heard anything stated like that probably a real simple thing it's bothering me don't say answer. I should know i'm in adv algebra.

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                • #9
                  Re: Prize to solve this problem

                  Just in algebra..

                  Ummmmm.... 4.239529857 and 2.13579857?

                  Yea, no...

                  They don'y exist? :lol:

                  Comment


                  • #10
                    Re: Prize to solve this problem

                    I just can't remember. I want to say you use the quad formula or something but idk. The order paired things kind of threw me off still doesn't make sence.
                    Last edited by FlAmMaBle; 09-28-2006, 02:27 PM.

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                    • #11
                      Re: Prize to solve this problem

                      *confused...*

                      Made by me

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                      • #12
                        Re: Prize to solve this problem

                        There is no such thing;
                        its impossible the only numbers that can go into 14 are 1, 2 and 7.
                        :love:

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                        • #13
                          Re: Prize to solve this problem

                          3 1/2?
                          "Faith is the art of holding on to things your reason has once accepted in spite of your changing moods." -- C.S. Lewis

                          Comment


                          • #14
                            Re: Prize to solve this problem

                            3 1/2 + 3 1/2 = 7
                            3.5x3.5=12.25...yeah that doesn't work
                            "Faith is the art of holding on to things your reason has once accepted in spite of your changing moods." -- C.S. Lewis

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                            • #15
                              Re: Prize to solve this problem

                              none so far. it does work. the answer is a possible answer.
                              Take a look at my past signatures and avatars! And maybe some extra stuff! http://www.picturetrail.com/gallery/...ris221&x=0&y=0

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                              • #16
                                Re: Prize to solve this problem

                                its a decimal right?

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                                • #17
                                  Re: Prize to solve this problem

                                  its an ordered pair. like (1,-2) Im gonna word it better.
                                  graph the quadratic function that results from the above stated problem, and find the two real solutions by graphing. (thats what the whole thing up there said you just had to know what it meant)
                                  Take a look at my past signatures and avatars! And maybe some extra stuff! http://www.picturetrail.com/gallery/...ris221&x=0&y=0

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                                  • #18
                                    Re: Prize to solve this problem

                                    3.14?
                                    lmaoo
                                    :love:

                                    Comment


                                    • #19
                                      Re: Prize to solve this problem

                                      do u use x & y intercepts? give me a minute im thinking!
                                      nvm u dont! im solving it hold on! im only in algebra im in the 7th grade BTW
                                      im a course ahead.. lets see if i can get this

                                      Comment


                                      • #20
                                        Re: Prize to solve this problem

                                        Originally posted by Ilovevmk! View Post
                                        do u use x & y intercepts? give me a minute im thinking!
                                        nvm u dont! im solving it hold on! im only in algebra im in the 7th grade BTW
                                        im a course ahead.. lets see if i can get this
                                        :blush:
                                        Oh come on you make me feel stupid; I'm in 9th & in pre algebra..
                                        :love:

                                        Comment

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